Fix incorrect notes
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@ -370,8 +370,8 @@ $$\begin{split}
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Für das aktuelle Beispiel ergibt das folgendes:
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Für das aktuelle Beispiel ergibt das folgendes:
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$$\begin{split}
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$$\begin{split}
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\int{\frac{2}{x - 1} + \frac{2}{x - 2} + \frac{3}{(x - 2)^2}}dx & = \int{\frac{2}{x - 1}} - \int{\frac{2}{x - 2}} + \int{\frac{3}{(x - 1)^2}} \\
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\int{\frac{2}{x - 1} + \frac{2}{x - 2} + \frac{3}{(x - 2)^2}}dx & = \int{\frac{2}{x - 1}} - \int{\frac{2}{x - 2}} - \int{\frac{3}{(x - 1)^2}} \\
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& = 2 \cdot \int{\frac{1}{x - 1} - 2 \cdot \int{\frac{1}{x - 2}}} + 3 \cdot \int{\frac{1}{(x - 2)^2}} \\
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& = 2 \cdot \int{\frac{1}{x - 1} - 2 \cdot \int{\frac{1}{x - 2}}} - 3 \cdot \int{\frac{1}{(x - 2)^2}} \\
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& = 2 \cdot \ln(|x - 1|) - 2 \cdot \ln(|x - 2|) - 3 \cdot \frac{1}{x - 2} + c
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& = 2 \cdot \ln(|x - 1|) - 2 \cdot \ln(|x - 2|) - 3 \cdot \frac{1}{x - 2} + c
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\end{split}$$
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\end{split}$$
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